 Time Limit:10000ms
Case Time Limit:1000ms
Memory Limit:256MB

### Description

Find a pair in an integer array that swapping them would maximally decrease the inversion count of the array. If such a pair exists, return the new inversion count; otherwise returns the original inversion count.

Definition of Inversion: Let (A, A … A[n], n <= 50) be a sequence of n numbers. If i < j and A[i] > A[j], then the pair (i, j) is called inversion of A.

Example:
Count(Inversion({3, 1, 2})) = Count({3, 1}, {3, 2}) = 2
InversionCountOfSwap({3, 1, 2})=>
{
InversionCount({1, 3, 2}) = 1 <– swapping 1 with 3, decreases inversion count by 1
InversionCount({2, 1, 3}) = 1 <– swapping 2 with 3, decreases inversion count by 1
InversionCount({3, 2, 1}) = 3 <– swapping 1 with 2 , increases inversion count by 1
}

### Input

Input consists of multiple cases, one case per line.Each case consists of a sequence of integers separated by comma.

### Output

For each case, print exactly one line with the new inversion count or the original inversion count if it cannot be reduced.

Sample Input
Sample Output

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